$\newcommand{\diff}{\,\text{d}}$

Geometry proof

This problem is adapted from problem #15 in section 3.4 of

Rhoad, R., Milsaukas, G., & Whipple, R. Geometry for Enjoyment and Challenge (New Edition). McDougal Littell, 1991. Page 137.

All references to theorems are taken taken this text.

Problem:

Given the figure

and the statements

$\overline {AB} \cong \overline{AC}$

$\overline {BD} \cong \overline{CE}$,

Prove: $\angle ABC \cong \angle ACB$

Comment: This could be proved in a single step using Theorem 21 (page 149) "If two sides of a triangle are congruent, the angles opposite the sides are congruent." However, this theorem will not be proved until a later chapter, so we must arrive at our proof by different means.

Historical note: This problem as actually a disguised version of the "pons asinorum" (or "Bridge of Asses") proof from Euclid's Elements. In that problem only the $\triangle ABC$ is given, and the the student must prove that if it is isosceles then its base angles are congruent. The proof given is surprisingly complex (though simpler proofs are known); hence it was said to separate the students who could understand it from the "asses" who could not.

Solution:

Statement Justification
1. $\overline {AB} \cong \overline{AC}$ Given
2. $\overline {BD} \cong \overline{CE}$ Given
3. $\overline {AD} \cong \overline{AE}$ Addition Property
(1, 2)
4. $\angle A \cong \angle A$ Reflexive Property
5. $\triangle ADC \cong \triangle AEB$ SAS
(3, 4, 1)
6. $\overline{DC} \cong \overline{EB}$ CPCTC
(5)
7. $\angle D \cong \angle E$ CPCTC
(5)
8. $\triangle BDC \cong \triangle CEB$ SAS
(2, 7, 6)
9. $\angle DBC \cong \angle ECB$ CPCTC
(8)
10. $\angle DBC$ is supp. to $\angle CBA$ Def. of supp. $\angle$'s
11. $\angle ECB$ is supp. to $\angle BCA$ Def. of supp. $\angle$'s
12. $\angle DBC$ is supp. to $\angle BCA$ Substitution
(9, 11)
13. $\angle CBA \cong \angle BCA$ Transitive property
(10, 12)

Q. E. D.